LongLifeLearner
New member
- Joined
- Oct 23, 2020
- Messages
- 15
The question asked to write an equation of the perpendicular bisector of the line segment joining -1-3i and 2-i in term of z , specifically in the form of Im ((a+bi)z)=c
by wrote into:
|z-(-1-3i)|=|z-(2-i|
And solve it accordingly i get
3x+2y=-5/2
Knowing the answer is Im((2+3i)z)=-5/2
But i m still struggle to find out what is the principle behind.
Hope someone can assist me the easy way to identify an equation, how to write an equation on complex plane in the form either in Re((a+bi)z) or Im((a+bi)z) especially when involved 2 points, or a point with a known slope. Thanks in advance
by wrote into:
|z-(-1-3i)|=|z-(2-i|
And solve it accordingly i get
3x+2y=-5/2
Knowing the answer is Im((2+3i)z)=-5/2
But i m still struggle to find out what is the principle behind.
Hope someone can assist me the easy way to identify an equation, how to write an equation on complex plane in the form either in Re((a+bi)z) or Im((a+bi)z) especially when involved 2 points, or a point with a known slope. Thanks in advance