Using all the letters from A, B, C, E , F, F, G. How many 7 letter permutations are there if the first letter has to be a consonant.
My work:
Total 7 letter permutations are 7! / 2! = 2520 since there are 2 Fs
Number of permutations that start with either A or E:
There are two options for the first letter (A or E) and there are 6!/2! ways to arrange the other 6 letters so that they are after the first letter.
So the number of permutations that start with either A or E = 2*6!/2! = 720
My answer = 2520-720 = 1800
Is my answer correct?
My work:
Total 7 letter permutations are 7! / 2! = 2520 since there are 2 Fs
Number of permutations that start with either A or E:
There are two options for the first letter (A or E) and there are 6!/2! ways to arrange the other 6 letters so that they are after the first letter.
So the number of permutations that start with either A or E = 2*6!/2! = 720
My answer = 2520-720 = 1800
Is my answer correct?