Permutations

carebear

New member
Joined
Aug 30, 2010
Messages
45
In how many ways can 3 men and 2 women be arranged in a row if there is a man at the end of each row?

I get:

3 x 2 x 1 x 1 x 2 = 12
M x W x M x W x M

The answer says 36...please help...what am I missing?
 
carebear said:
In how many ways can 3 men and 2 women be arranged in a row if there is a man at the end of each row?

I get:

3 x 2 x 1 x 1 x 2 = 12
M x W x M x W x M

The answer says 36...please help...what am I missing?

What is meant by each here?

There is only one row - correct?
 
carebear & edit said:
In how many ways can 3 distinguishable men and 2 distinguishable women be arranged in a row if there is a man at each end of the row?

I get:

3 x 2 x 1 x 1 x 2 = 12
M x W x M x W x M

The answer says 36...please help...what am I missing?

carebear,

I believe you meant what is shown in this quote box.
 
If "lookagain"'s interpretation is correct - (which should be) - then

You have three men to fill two positions at the end of the row - 6 ways

You have 3 people filling 3 inside positions - 6 ways
 
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