perimeter of the triangle with vertices

V

viet

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Nov 19, 2005
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Find the perimeter of the triangle with the vertices at
(1, -1), (-5, 3), and (-4, -2).

im use the distances formula, not sure if its the right way to do it.
i made (1, -2) point A, (-5, 3) point B, and (-4, -2) point C.
from point AB i got sqrt(28), AC is sqrt(34), and BC is sqrt(2)
when i added up sqrt(28)+sqrt(34)+sqrt(2) = 12.5366
the answer is wrong, can someone help please?
 
There appears to be a typo in what you've posted, and I'm not getting values close to yours. Please proof the exercise and reply with corrections, showing your steps.

Thank you.

Eliz.
 
ya i made a typo sorry. i got the correct answer, thanks!!.
the quest is "Find the perimeter of the triangle with the vertices at
(1, -1), (-5, 3), and (-4, -2)."

i use the distance forumla: d = sqrt((X1-X2)^2 + (Y1-Y2)^2))
AB = sqrt(52)
BC = sqrt(26)
AC = sqrt(26)

AB+BC+AC = 17.4091
 
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