performing operation 4x^2 / (x^2 - 4x + 4) / (2x) / (x^2 - 4

[kpx001]

4x^2 / (x^2 - 4x + 4) / (2x) / (x^2 - 4)

4x^2 / (x-2)(x-2) / 2x /(x-2)(x+2)

4x^2 / (x-2)(x-2) times (x-2)(x+2)/(2x)

2x(x+2) / (x-2) = final?

 

[galactus]

You got it. Very good

 

[Deleted member 4993]

Re: performing operation 4x^2 / (x^2 - 4x + 4) / (2x) / (x^2

should be written as:

[4x^2 / (x^2 - 4x + 4) ] / [(2x) / (x^2 - 4)]

[4x^2 / {(x-2)(x-2)}] / [2x /{(x-2)(x+2)}]

4x^2 / [(x-2)(x-2)] * (x-2)(x+2)/(2x)

2x(x+2) / (x-2) = final?