Percentages and pounds to maximize revenue: Jumbo Java sells 2 diff. coffee blends...

O

oregon789

New member
Joined
Jan 22, 2017
Messages
17
Jumbo Java sells two different coffee blends: House blend and Gourmet blend. The House blend is 90% Antigua and 10% Kona and it sells for $10/lb, while the Gourmet blend is 80% Antigua and 20% Kona and it sells for $11/lb. Jumbo Java has a limited amount of Antigua and Kona beans on hand. How many pounds of the two blends should they mix to maximize revenue if they have 72 lbs Antigua beans and 10 lbs Kona beans on hand?

I'm supposed to write an equation (or 2?) and set it equal to or less than whatever number.
 
oregon789 said:
Jumbo Java sells two different coffee blends: House blend and Gourmet blend. The House blend is 90% Antigua and 10% Kona and it sells for $10/lb, while the Gourmet blend is 80% Antigua and 20% Kona and it sells for $11/lb. Jumbo Java has a limited amount of Antigua and Kona beans on hand. How many pounds of the two blends should they mix to maximize revenue if they have 72 lbs Antigua beans and 10 lbs Kona beans on hand?

I was thinking
to maximize z=10x+11y

subject to the constraints
.90x+.80y<=72
.10x+.20yL<=10
x>=0
y>=0
Click to expand...
Okay; I'll guess that you defined your variables as follows:

. . .x: pounds of house blend

. . .y: pounds of gourmet blend

If correct, then your set-up looks good. Now graph the feasibility region, and plug the corner points into your optimization equation. Find the corner point that maximizes revenue. (Or, if you're the one who posted this question at the pay-$14.95-for-help site yesterday, check the response posted by the helper there.) ;)
 
Last edited by a moderator:
You must log in or register to reply here.
Top