Percentage Probability

Sacha Singh

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Mar 9, 2020
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Hi All,

If I had a 70% chance of accomplishing that goal but I had 3 attempts to accomplish it, what is my overall chance of success? I'm thinking it goes up but not sure by what percentage. Pls help.

Sacha
 
"goes up" from what? Because of what?

Question is ambiguous. I'll answer two ways.


If you had a 70% chance of success, given three tries, then you had a 30% chance of failure, given 3 tries. Thus, your overall chance of failure gives: [math]\left[p(Failure\;on\;one\;try)\right]^{3} = 0.30\;\rightarrow\;p(Failure\;on\;one\;try) = 0.67\;thus,\;p(success\;on\;one\;try) = 1 - 0.67 = 0.33[/math]
That seems to be more in line with what you SAID, but it may not be what you MEANT.

If you MEANT, [math]p(success\;on\;one\;try) = 0.70,[/math] then [math]p(failure\;on\;one\;try) = 1 - 0.70 = 0.30[/math]. Thus, [math]p(failure\;given\;three\;tries) = 0.30^{3} = 0.027[/math] and we have [math]p(success\;given\;three\;tries) = 1 - 0.027 = 0.973[/math]
It's important to be clear.
 
If I had a 70% chance of accomplishing that goal but I had 3 attempts to accomplish it, what is my overall chance of success? I'm thinking it goes up but not sure by what percentage. Pls help.
I'll try a second interpretation. Suppose you meant this:

If I have a 70% chance of accomplishing a goal on any one try, but I have 3 attempts to accomplish it, what is my overall chance of success?​

Then the probability of succeeding on any one of the three tries is 1 minus the probability of failing on all three.

The probability of failing on one try is [MATH]1 - 0.70 = 0.30[/MATH].

The probability of failing on all three is [MATH]0.30^3 = 0.027[/MATH].

So the probability of succeeding at least once is [MATH]1 - 0.027 = 0.973 = 97.3\%[/MATH]. Yes, that's a significant improvement.

You'll notice that this is just tkhunny's work turned inside out.
 
Assuming that the 70% was for one try. Then of course the probability will increase if you get more chances.
 
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