Percent error

S

spezialize

New member
Joined
Sep 27, 2005
Messages
26
A ball has radius 3mm and may have an error in measurement up to .01mm.

How do I get the maximum possible error in volume..? I know to get the percent error i just multiple that by 100 right?
 
What is the minimum possible radius? What volume does this give you?

What is the maximum possible radius? What volume does this give you?

What is the desired radius? What volume does this give you?

What is the difference between the desired volume and the max and min possible volumes? What is the maximum difference?

Eliz.
 
stapel said:
What is the minimum possible radius? What volume does this give you?

What is the maximum possible radius? What volume does this give you?

What is the desired radius? What volume does this give you?

What is the difference between the desired volume and the max and min possible volumes? What is the maximum difference?

Eliz.
Click to expand...

I have no clue....can anyone help me through
 
A ball has radius 3mm and may have an error in measurement up to .01mm

Vol = (4/3) pi r^3

smallest possible size of r = 3-0.01 = 2.99mm

largest possible size of r = 3 + 0.01 = 3.01mm

Do the volume calculation with each of these sizes.
 
You've been given the radii. You've been given the volumes. Which part of finding the percentage difference (from back in pre-algebra) do you not understand?

Please be specific. Thank you.

Eliz.
 
Really? You don't even know how to add 0.01 to 3? Or how to subtract 0.01 from 3? Or how to use the volume formula for a sphere?

You're in calculus, which means you have passed through arithmetic, pre-algebra, algebra, and geometry. Saying "I don't know how to do any of it" wouldn't seem to make any sense in this context. Please be specific about where you are stuck. Showing your work would be very helpful.

Thank you.

Eliz.
 
as before........

Vol = (4/3) pi r^3

smallest possible size of r = 3-0.01 = 2.99mm

largest possible size of r = 3 + 0.01 = 3.01mm

Do the volume calculation with each of these sizes.

V1 = (4/3) (22/7) ((2.99)^3)

V2 = (4/3) (22/7) ((3.01)^3)


maximum possible error in volume = V2 - V1

now have a go...
 
You must log in or register to reply here.
Top