Percent Difference?

[george22]

Hello,

I am new to this so any help will be appreciated. I am struggling with a problem that deals with either error difference or percent difference.

1. F = 1.8C + 32. If a student added 30 to twice the Celsius (F = 2C + 30) What error (difference) would he find?



2. p / 100 = | a - m | / a with a 5% error, a = actual measurement, m = measured measurement, which would be the closest?

I. 9500
II. 10000
III. 10500
IV. none

 

[daon]

The percent error is given by:

Err = 100 *[(Anticipated Value - Expirimental Value)/(Anticipated Value)]

In this case,

Err = 100*[(1.8C+32) - (2C + 30)]/(1.8C + 32)

Note that your final answer depends on C and will have different values depending on what temperature you are attempting to calculate.

 

[george22]

Thanks Daon,

Your help is greatly appreciated!

 

[tkhunny]

It doesn't work very well for:

Anticipated Value = 0

I have yet to see a rational substitute for this condition.