IloveManUtd
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I've got a question that asks me to express [5x+9/(x+3)^2] as partial fractions. I do not know how to express the denominator. Please help. Thx
Partial Fractions
- Thread starter IloveManUtd
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mmm4444bot
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The set-up is: (5x + 9)/(x + 3)^2 = A/(x +3) + B/(x + 3)^2
On the right-hand side, get a common denominator, and combine the ratios.
Equating numerators on each side then leads to:
Ax + 3A + B = 5x + 9
Equating coefficients yields:
Ax = 5x
and
3A + B = 9
Solve this system, to find A and B.
On the right-hand side, get a common denominator, and combine the ratios.
Equating numerators on each side then leads to:
Ax + 3A + B = 5x + 9
Equating coefficients yields:
Ax = 5x
and
3A + B = 9
Solve this system, to find A and B.
BigGlenntheHeavy
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\(\displaystyle IloveManUtd, \ once \ you \ learn \ the \ system, \ to \ avoid \ all \ the \ grunt \ work,\)
\(\displaystyle (if \ you \ have \ a \ trusty \ TI-89) \ then \ do \ this:\)
\(\displaystyle F2,3,[(5x+9)/(x+3)^2,x] \ = \ \frac{5}{x+3}-\frac{6}{(x+3)^2}\)
\(\displaystyle (if \ you \ have \ a \ trusty \ TI-89) \ then \ do \ this:\)
\(\displaystyle F2,3,[(5x+9)/(x+3)^2,x] \ = \ \frac{5}{x+3}-\frac{6}{(x+3)^2}\)