Partial Fraction Decomposition Procedure

[RickPalomino]

I've reached a roadblock on my homework assignment, which is a partial fraction with a cubed power. As with repeated factors, such as x² on previous problems, my initial idea was to solve them in the same way. As in, 1/x²(X+1) = A/x + B/x² + C/(X+1) for example. The question given is:
6x²+1
-------
x²(x-1)³

So my question in a nutshell is, would this Partial Fraction Decomposition be solved using:
A/x + B/x² + C/(x-1) + D/(x-1)² + (x-1)³ ?

 

[skeeter]

I've reached a roadblock on my homework assignment, which is a partial fraction with a cubed power. As with repeated factors, such as x² on previous problems, my initial idea was to solve them in the same way. As in, 1/x²(X+1) = A/x + B/x² + C/(X+1) for example. The question given is:
6x²+1
-------
x²(x-1)³

So my question in a nutshell is, would this Partial Fraction Decomposition be solved using:
A/x + B/x² + C/(x-1) + D/(x-1)² + (x-1)³ ?

bingo!

 

[RickPalomino]

Okay, thanks for the help.

 

[Deleted member 4993]

I've reached a roadblock on my homework assignment, which is a partial fraction with a cubed power. As with repeated factors, such as x² on previous problems, my initial idea was to solve them in the same way. As in, 1/x²(X+1) = A/x + B/x² + C/(X+1) for example. The question given is:
6x²+1
-------
x²(x-1)³

So my question in a nutshell is, would this Partial Fraction Decomposition be solved usingCorrecting a small typo)
A/x + B/x² + C/(x-1) + D/(x-1)² + E/(x-1)³ ?