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Guest
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I have a homework question which says
Given:
A particular solution of y'' - y' - 2y = 20e^4t is f1 = 2e^4t
A particular integral of y'' - y' - 2y = 5 - 6t is f2 = 3t - 4
Find the general solution of y'' - y' - 2y = -5e^4t + 20 - 24t
The instructor says to refer to the theory in the book wich states:
Hypothesis.
1. Let f1 be a particular integral of
a0(x)y^n + a1(x)y^(n-1) + .... an-1(x)y' + an(x)y = F1(x)
2. Let f2 be a particular integral of
a0(x)y^n + a1(x)y^(n-1) + .... an-1(x)y' + an(x)y = F2(x)
Conclusion.
a0(x)y^n + a1(x)y^(n-1) + .... an-1(x)y' + an(x)y = k1F1(x) + k2F2(x)
I get lost trying to understand theory. Can someone please point me in the right direction?
Given:
A particular solution of y'' - y' - 2y = 20e^4t is f1 = 2e^4t
A particular integral of y'' - y' - 2y = 5 - 6t is f2 = 3t - 4
Find the general solution of y'' - y' - 2y = -5e^4t + 20 - 24t
The instructor says to refer to the theory in the book wich states:
Hypothesis.
1. Let f1 be a particular integral of
a0(x)y^n + a1(x)y^(n-1) + .... an-1(x)y' + an(x)y = F1(x)
2. Let f2 be a particular integral of
a0(x)y^n + a1(x)y^(n-1) + .... an-1(x)y' + an(x)y = F2(x)
Conclusion.
a0(x)y^n + a1(x)y^(n-1) + .... an-1(x)y' + an(x)y = k1F1(x) + k2F2(x)
I get lost trying to understand theory. Can someone please point me in the right direction?