Parametric equation: An outfielder throws a baseball to the

[vmbs]

Please help me with this problem, I don't have a clue how to gyo about solving it!

An outfielder throws a baseball to the catcher 120 ft away to prevent a runner from scoring. The ball is released 6 ft abovethe ground with a horizontal speed of 25 ft per second. The catcher holds his mitt 2ft off the ground.

a. Find the parametric equations that describe the path of the ball.

b. When does the ball reach its maximum altitude? What is the max altitude? How far has it travelled horizontally by that time?

c. Will the catcher catch the ball?


Thank you!!!!!!!

 

[Gene]

Starting with the fielder at 0,0, the parametric equations are:
V_x = 25
x = 25t

V_y = dy/dt
V_y = V₀ - at
y = 6 + V₀t - .5at²

So when the ball is caught,
x = 120,
y = 2
t = 4.8
y = 6 + V₀*4.8 - .5a*4.8² = 2
Slove for V₀
Solve for V_y = 0

 

[arthur ohlsten]

I noticed you did not receive the parametric equation
if the equations are

x=vt
y=6+V[0] t-.5at^2

from x=vt solve for t
t=x/v substitute for t in second equation

y=6+[V[0]/v] x -.5ax^2/v^2

To find the parametric equation replace the variable t with its x or y equivalent
Arthur