parabola

dgonz033

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Nov 11, 2012
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You learn the towers are 310 meters apart. You set up a Cartesian coordinate system with one end of the arch at the origin and the other end is at 310 meters from the start. To find the third point on the arch you measure a vertical distance of .6 meters when the horizontal distance is 1 meter. You assume that the arch is parabolic. what is the third point?
 
You learn the towers are 310 meters apart. You set up a Cartesian coordinate system with one end of the arch at the origin and the other end is at 310 meters from the start. To find the third point on the arch you measure a vertical distance of .6 meters when the horizontal distance is 1 meter. You assume that the arch is parabolic. what is the third point?

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Hello, dgonz033!

What is the original wording of the problem?
As given, the problem is quite silly.


You learn the towers are 310 meters apart.
You set up a Cartesian coordinate system with one end of the arch at the origin
and the other end is at 310 meters from the start.
To find the third point on the arch you measure a vertical distance of 0.6 meters
when the horizontal distance is 1 meter.
You assume that the arch is parabolic.
What is the third point?

I've come in during the middle of the movie.
. . What towers?
. . What arch?
. . Whatever!

It seems we have one end at \(\displaystyle (0,0)\), the other at \(\displaystyle (310,0).\)

We have a third point at \(\displaystyle (1,0.6).\)

"What is the third point?"
Um, I'll get back to you . . .
 
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