Pair of Functions (F-G)(3)

[ghostly]

For the pair of functions , find (f-g)(3)

f(x)=2x^2+3 g(x)=x-4

what I have so far is

[2(3)^2+3]-(3-4) --->I distributed the negative sign(don't know if that's correct)

3^2=9(2)=18+3=21

21-3+4=22

Can anyone confirm please? Thanks

 

[Deleted member 4993]

For the pair of functions , find (f-g)(3)

f(x)=2x^2+3 g(x)=x-4

what I have so far is

[2(3)^2+3]-(3-4) --->I distributed the negative sign(don't know if that's correct)......... That is legal

3^2=9(2)=18+3=21........... This is incorrect "mathematical" statements.

21-3+4=22

Can anyone confirm please? Thanks

Correct - except as noted.

 

[HallsofIvy]

For the pair of functions , find (f-g)(3)

f(x)=2x^2+3 g(x)=x-4

what I have so far is

[2(3)^2+3]-(3-4) --->I distributed the negative sign(don't know if that's correct)

3^2=9(2)=18+3=21

Don't write "bits and pieces" and set them equal! 3^2= 9, but that is NOT equal to 9(2). And that is not equal to 18+ 3.
What you mean is [2(3)^2+ 3]- (3- 4)= [2(9)+ 3]- (-1)= [18+ 3]+ 1= 21+ 1= 22.

21-3+4=22

Can anyone confirm please? Thanks