Hckyplayer8
Full Member
- Joined
- Jun 9, 2019
- Messages
- 269
A box with a square base and no top has a volume of 32ft3. What dimensions use the lest amount of material (give a min surface area)?
V = (L)(W)(H)
A = [2(H)(W)] + [2(H)(L)] + (W)(L)
So subbing x and y values for the above...we know the base is square thus
V = (x2)(y)
A = 4xy + x2
V = 32 so
32 = x2 (y)
y = 32 / x2
S (A) = x2 + 4x(32 / x2) = x2 + 128 / x
S'(A) = 2x - 128 / x2
How am I looking so far?
V = (L)(W)(H)
A = [2(H)(W)] + [2(H)(L)] + (W)(L)
So subbing x and y values for the above...we know the base is square thus
V = (x2)(y)
A = 4xy + x2
V = 32 so
32 = x2 (y)
y = 32 / x2
S (A) = x2 + 4x(32 / x2) = x2 + 128 / x
S'(A) = 2x - 128 / x2
How am I looking so far?