Let f(x)=3x5+5x4+9x+10 . Find the equation of the tangent line to f that has the smallest slope.
Do I start by taking the derivative of the function?
If so, Do I use Taylor expansion to find the equation or?
y-y1=m(x-x1) is the equation of the tangent line
not sure how to get there
Good - that would be the "form" of your final answer.
In the equation above - what is the slope of the line?
m is the slope, also known as f'(x)
Now - evaluate f'(x)...
Do you understand that the first derivative of a function is the slope of the function and thus the slope of the line tangent to the function?F'(x)=15x4+20x3+9 Correct
Do you understand that the first derivative of a function is the slope of the function and thus the slope of the line tangent to the function?
Do you understand that the first derivative of a function is itself a function?
How do you find local extrema of any differentiable function?
Is the first derivative of this function a differentiable function?
So how do you find its minimum and why would you want to?
The problem asks you to find the smallest slope. Does that not indicate to you a minimum? An extremum is either a minimum or a maximum. 90% of the mechanics of differential calculus is about finding a minimum or a maximum, in other words an extremum, of a differentiable function. The thinking comes in figuring what is the relevant function and whether the relevant extremum is a minimum or a maximum.Do I need to find local extrema?
Do I need to find local extrema?
y-y1=m(x-x1) is the equation of the tangent line
not sure how to get there
whiteti, is the instructor actually expecting the final form of the equation of the tangent line to be \(\displaystyle \ "y = mx + b \ ?"\)Good - that would be the "form" of your final answer.