Operations with functions questions

super_chris1234

New member
Joined
Mar 20, 2012
Messages
17
Hello,

I am currently having some difficulty with some functions questions. If anyone can provide me some insight as to how to solve these, that would be great.

Given f={(-3,5),(0,-2),(1,6),(2,3)} and 2x-4

How would I perform the followign operations?

1) f(g(x))


and

2) f(1)-g(1-k)

Any help is greatly appreciated

Thanks,

Chris
 
You have not defined g(x). Did you mean g(x) = 2x-4?

f(-3) = 5

g(What) = -3

f(0) = -2

g(What) = 0
 
It does make me uncomfortable when I get a second response and there is still no actual work shown.

I posed two questions, above. Each takes two little expressions. Answer these questions.
 
Sorry, wasn't thinking when asked those. These are just text book questions that got me confused.

The first one I tried to approach as follows:

f(g(x))

f(2x-4)

But, then I get stuck as I'm not sure what to do from there.



I attempted to solve the second one as follows:

f(1)-g(1-k)

6-2(1-k)-4

6-2+2k-4

2k=0

But, that's where I get stuck. My method doesn't seem right to me. As I know division by zero isn't possible. Any insight on this one is greatly appreciated
 
You're still stuck because you still didn't answer my questions.

g(What) = -3

g(What) = 0

Let's first see if you understand the notation.
 
What are you asking exactly? I'm not following you entirely. Even if someone was to provide the best way to approach this question, that would provide me some insight.
 
You have g(x) = 2x - 4

What value of 'x' is required to produce: g(What) = 2*(What) - 4 = -3

I think we have proven that you do not understand the notation. Please back up and read the section on Function Notation. Work a few more problems. Make sure you know what it means.

Something, when multiplied by 2 and subsquently having 4 subtracted from the product produces the value -3. What is that something?
 
Oh, I see what you were asking. Thanks. I will definitely go back into my text book and read up a bit. Thanks again
 
Top