musicgenes
New member
- Joined
- Aug 6, 2012
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- 2
I am reading a book called calculus made easy. I have always wanted to learn the subject and now that I am retired and decided to do so. I did well in pre calculus some 30 plus years ago and reviewed the subject through a video I purchased from the Teaching Company.
I am studying what is a function and have a question the book discusses as follows:
A slightly more complicated example of a one to one function is the relation of a square's side to its diagonal. So I know the following:
a squares diagonal is the hypotenuse of an isoceles right triangle. Isoceles meaning two sides of a triangle are the same as are two of the angles.
Pythagorean therorem means that the square of the hypotenuse equals the sum of the other two squares sides.
Now I can visualize the triangle and each square drawn in relation to each side of the triangle. I know that a^2 + b^2 = c^2.
I am trying to figure out if a^2 + b^2 = c^2 are the areas or just the sides as in Area = length x length?
I want to figure out how to express the diagonal as a function of the squares side.
Sorry for the confusion. This might take a few questions before I catch on.
I am studying what is a function and have a question the book discusses as follows:
A slightly more complicated example of a one to one function is the relation of a square's side to its diagonal. So I know the following:
a squares diagonal is the hypotenuse of an isoceles right triangle. Isoceles meaning two sides of a triangle are the same as are two of the angles.
Pythagorean therorem means that the square of the hypotenuse equals the sum of the other two squares sides.
Now I can visualize the triangle and each square drawn in relation to each side of the triangle. I know that a^2 + b^2 = c^2.
I am trying to figure out if a^2 + b^2 = c^2 are the areas or just the sides as in Area = length x length?
I want to figure out how to express the diagonal as a function of the squares side.
Sorry for the confusion. This might take a few questions before I catch on.