One more please help

No, so what I am looking for is 8^something that equals to 2?

I am really lost in these type of problems.
 
Hint: \(\displaystyle 64^{\frac{1}{3}} = 4\)
 
\(\displaystyle 8^x = 2\)

\(\displaystyle (2^3)^x = 2\)

\(\displaystyle 2^{3x} = 2^1\)

can you solve for x now ???
 
Thank you. I have been out of school for about 16 years and I can't remember this stuff. Thank you everyone.
 
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