Nikkimarie
New member
- Joined
- May 8, 2020
- Messages
- 15
What does the overall perimeter consist of? How do we find the lengths of all the components?Hi! I was doing this math problem (number 5) and I am so confused by what I did wrong. I know I didn’t do it right if someone could help that would be amazing!
Hi! I was doing this math problem (number 5) and I am so confused by what I did wrong. I know I didn’t do it right if someone could help that would be amazing!
The perimeter consists of inches and 90° angles so four angles of 90. That is one circle and then it has two sides of 6 inches but other the. That I am lostWhat does the overall perimeter consist of? How do we find the lengths of all the components?
Wouldnt R be 90° and four 90° wouldn’t it then be 360? So one whole circle out of the equation?View attachment 18627
I think this problem is missing some information.
According my interpretation (assuming 4 quarter circles of radius 'r' has been cut out from the rectangle)
Perimeter = 2 * [6 + (6 +2r)] - 4 * 2 * r + 4 * (2 * π * r / 4) = 24 + r * ( 2 * π - 4)
Without measurement for 'r' - it cannot be done.
Also what if I put it in terms of pi and then converted PI to Inches?View attachment 18627
I think this problem is missing some information.
According my interpretation (assuming 4 quarter circles of radius 'r' has been cut out from the rectangle)
Perimeter = 2 * [6 + (6 +2r)] - 4 * 2 * r + 4 * (2 * π * r / 4) = 24 + r * ( 2 * π - 4)
Without measurement for 'r' - it cannot be done.
R is radius of the circle used to make 4 cut outs, it's distance, measured in inches. 90° is an angle of the rectangle, measured in degrees.Wouldnt R be 90° and four 90° wouldn’t it then be 360? So one whole circle out of the equation?
What if since two sides of the Square are 6” and with including the circle cuts the other side is also 6’ and since each circle part is the same size they would be 2 inches each? If that makes any senseR is radius of the circle used to make 4 cut outs, it's distance, measured in inches. 90° is an angle of the rectangle, measured in degrees.
I retried it and I got thisR is radius of the circle used to make 4 cut outs, it's distance, measured in inches. 90° is an angle of the rectangle, measured in degrees.
I don't follow. Where do you see a square? How did you get 2 inches?What if since two sides of the Square are 6” and with including the circle cuts the other side is also 6’ and since each circle part is the same size they would be 2 inches each? If that makes any sense
yes sorry, the square the shape. Forget about the circle quarters and imagine them filled in. That is a square because of the information given. And the perimeter consist of two 6” sides and then 2 unknown sides but if you fill it in with the circles it’s then four 6” sidesI don't follow. Where do you see a square? How did you get 2 inches?
First of all, it does look like there is missing info - without knowing the radius I don't see how to solve it.
In any case, forget for a moment about numbers. Can you answer my first question?
The dimensions of the rectangle I do not know but the radius of the circle I believe is 1 inch. The four arcs equal one circle yesYou have four \(90^o\) arcs. The centre of each would have been a vertex of a rectangle.
What would be the dimensions of that rectangle ? What is the radius of the arcs?
Do the four congruent arcs compost a circle?
I cross multiplied using the arch length and I believe the radius is 1Y
yes sorry, the square the shape. Forget about the circle quarters and imagine them filled in. That is a square because of the information given. And the perimeter consist of two 6” sides and then 2 unknown sides but if you fill it in with the circles it’s then four 6” sides
I don't see a square! I see a rectangle. Its height is 6in. Its length is unknown.Y
yes sorry, the square the shape. Forget about the circle quarters and imagine them filled in. That is a square because of the information given. And the perimeter consist of two 6” sides and then 2 unknown sides but if you fill it in with the circles it’s then four 6” sides
The arch length I believe is 0.5 as seen in my attachment. Yes I see what you are saying with the perimeter sorry about that. I believe the radius is 1 inch aswelI don't see a square! I see a rectangle. Its height is 6in. Its length is unknown.
What I wanted you to say: the perimeter consists of lengths of 4 straight segments and 4 arcs. Do you see it?
Now, back to numbers.
2 of the (horizontal) segments are 6in.
2 vertical segments ?
Arc length = ? What's the formula?
Why is radius 1? What's the formula for arc length?The arch length I believe is 0.5 as seen in my attachment. Yes I see what you are saying with the perimeter sorry about that. I believe the radius is 1 inch aswel
A circle with \(1\) has a circumference of \(2\pi\). What is one fourth of that?The arch length I believe is 0.5 as seen in my attachment. Yes I see what you are saying with the perimeter sorry about that. I believe the radius is 1 inch aswel
And I believe the radius is 1 because using this formula the circumference is 2Why is radius 1? What's the formula for arc length?
0.5!A circle with \(1\) has a circumference of \(2\pi\). What is one fourth of that?