One farmer has 119 sheep; another has 73. After they each sell same mumber of....

[A_BMT02]

One farmer has 119 sheep and another has 73.After they each sell the same mumber of sheep, one is left with three times as many sheep as the other. How many sheep did each sell.

The answer is 50 sheep.
Please i need the workings as soon as possible. Thanks.

 

[Deleted member 4993]

One farmer has 119 sheep and another has 73.After they each sell the same mumber of sheep, one is left with three times as many sheep as the other. How many sheep did each sell.

The answer is 50 sheep.
Please i need the workings as soon as possible. Thanks.

What are your thoughts?

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[A_BMT02]

Word problems

Can we hurry up and do this please.

My thoughts are that i think the equation is 119-x =3x and 73-x=x
Where x is thr subtracted number.

 

[Deleted member 4993]

Can we hurry up and do this please.

My thoughts are that i think the equation is 119-x =3y and 73-x=y
Where x is thr subtracted number.

Good! (note the correction above)

Then

119 - x = 3 * (73 - x)

Solve for 'x'

This is your problem - so you need to hurry up and do this!!!

 

[Deleted member 4993]

One farmer has 119 sheep and another has 73.After they each sell the same mumber of sheep, one is left with three times as many sheep as the other. How many sheep did each sell.

The answer is 50 sheep.
Please i need the workings as soon as possible. Thanks.

Solution posted by OP:

119-x=3(73-x)
119-x=219-3x
119-219=-3x+x
-100=-2x
x=-100 divided by -2
=50
Thank you sooo much.