Number Theory - Divisors

kiddopop

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Sep 14, 2009
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For a = 238000 = 2^4 * 5^3 * 7 * 17 and b = 299880 = 2^3 * 3^2 * 5 * 7^2 * 17

(a) How many positive divisors does ab have?

(b) What is the smallest positive integer n so that ab divides n^3?
 
kiddopop said:
For a = 238000 = 2^4 * 5^3 * 7 * 17 and b = 299880 = 2^3 * 3^2 * 5 * 7^2 * 17

(a) How many positive divisors does ab have?

(b) What is the smallest positive integer n so that ab divides n^3?

Start with

a*b = 2[sup:afxug69g]7[/sup:afxug69g] * 3[sup:afxug69g]2[/sup:afxug69g] * 5[sup:afxug69g]4[/sup:afxug69g] * 7[sup:afxug69g]3[/sup:afxug69g] * 17[sup:afxug69g]2[/sup:afxug69g]

Please show us your work, indicating exactly where you are stuck - so that we may know where to begin to help you.

You have posted 10 problems - but you have not shown one line of work!!!
 
I had that much...I just didn't know where to start.

And I generally have issues starting the problems...I mostly understand them if I get help getting started...but getting started is where I get stuck, so there's no work to show.
 
If you did have that much - why not tell us to start with.

We could discuss the next step then.

What does your textbook say about these problems?

Did you do a google search - what did you find?
 
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