number of ways to seat n couple in row of 2n chairs so that

wheatwoman

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In how many ways can n married couples be seated in a row of 2n chairs with no husband seated next to his wife?

Every other seat could be a !(factorial) but I'm not sure how to do it.

Any help would be appreciated.
 
Re: Discrete Math Question

wheatwoman said:
In how many ways can n married couples be seated in a row of 2n chairs with no husband seated next to his wife?

Every other seat could be a !(factorial) but I'm not sure how to do it.

Any help would be appreciated.

Hint:

Tie two chairs together (make loveseat) - total n love-seats. Tie the couples together - real tight.... :wink:

Now how many ways can you seat 'n' "tied" couples in 'n' love-seats.

Then think.....
 
The best way to approach this question is to first calculate the number of ways to have at least one couple is seated together.
\(\displaystyle \sum\limits_{k=1}^n {\left( { - 1} \right)^{k + 1} { n \choose k} \left( {2n - k} \right)!\left( {2^k } \right)}\). (Take note of the powers of 2: HF or WH)

Now subtract that number from the total possible, \(\displaystyle (2n)!\).
 
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