number 2

drewski92

New member
Joined
Nov 22, 2011
Messages
3
this is problem number 2

find the point on the curve y=x ln(3x) which is nearest the point (1,0). Hint: use the distance formula.
 
Please do not post exercises without asking any questions of your own.

We would like to know what you've thought about or tried thus far. Only then can we determine where to begin helping you.

(Please read the post titled "Read Before Posting" for more guidelines on what to post.)



I guess that you're familiar with the distance formula. This formula uses coordinates of two points.

In your exercise, the coordinates of these points are:

(x, x*ln[3x]) and (1, 0)

After you substitute these coordinates into the distance formula, you'll have a function for the distance.

Take the derivative of this distance function, solve for the zero, and use that value of x to calculate the coordinates of the requested point.



Beyond this, I'm not sure what you need. If you would like more help, please be specific. Cheers :cool:
 
Top