In Q14 you have 3 equations with 3 unknowns [1], [2] and [3].![]()
![]()
![]()
I'm stuck on 14 and not sure where to go from here. I was also wondering if 15 was correct?
Thanks!
In Q14 you have 3 equations with 3 unknowns [1], [2] and [3].
Solve for [1] and [2] simultaneously, and then check solution in equation [3].
Rearrange [1] to get s = -3t - 2.
[3] is s = -1 + t
So -3t - 2 = -1 + t etc.....
In Q14 you have 3 equations with 3 unknowns [1], [2] and [3].
Solve for [1] and [2] simultaneously, and then check solution in equation [3].
Rearrange [1] to get s = -3t - 2.
[3] is s = -1 + t
So -3t - 2 = -1 + t etc.....
Here is my new answer. Does that mean -1 = -8.75 is the intersection? Or did I mess up somewhere?
Are these two lines skew lines?
\(\displaystyle \begin{align*}6+3t&=4-s \\-1+t&=s\\-4t&=5+5s \end{align*}\)I'm not sure. I was thinking that when I saw the answer, but the question wants me to find the intersection so I feel as though I did something wrong.
\(\displaystyle \begin{align*}6+3t&=4-s \\-1+t&=s\\-4t&=5+5s \end{align*}\)
Now unless you can find values of \(\displaystyle s~\&~t \) which satisfy each of those equations at the same time, then the lines are skew lines.