Question:
A Rectangle is 6m long by 5m wide. When each dimension is increased by X m, the area is triple. Find X
My work:
Original
5m * 6m = 30m^2
Increased:
(6+x)(5+x) = 90 --> (The old area tripled as stated in question)
So by FOILing I would get:
30+11x+x^2 = 90
Now I'm assuming I need to use the Quadratic Formula, or Complete the Square. So I would equal the Quadratic equation to ax^2+bx+c=0
x^2 + 11x - 60 = 0
Now do I just plug the numbers into the Quadratic formula to get 'X'?
A Rectangle is 6m long by 5m wide. When each dimension is increased by X m, the area is triple. Find X
My work:
Original
5m * 6m = 30m^2
Increased:
(6+x)(5+x) = 90 --> (The old area tripled as stated in question)
So by FOILing I would get:
30+11x+x^2 = 90
Now I'm assuming I need to use the Quadratic Formula, or Complete the Square. So I would equal the Quadratic equation to ax^2+bx+c=0
x^2 + 11x - 60 = 0
Now do I just plug the numbers into the Quadratic formula to get 'X'?
