not sure, and i apologize for that

[porkshoulder]

What is the solution of the system ?
solution#1:4x-3y=2 solution #2: 2x+y=-4
\
multiple choice : a.)(-1,-2) b.) (-2,-1) c.) (-2,1) d.) (1,2)
4x-3y=2
2x+y=-4-3

(6x+3y=-12)
-(4x-3y=2)=
10x=-10
x=-10/10=-1
x=1

4(-1)=3y=2
-4-3y=2
-3=6
y=2

is the answer c. or d. i'm guessing with d.

 

[Deleted member 4993]

What is the solution of the system ?
solution#1:4x-3y=2 solution #2: 2x+y=-4 --- These are not "solutions" - these are called "equations"\
multiple choice : a.)(-1,-2) b.) (-2,-1) c.) (-2,1) d.) (1,2)

You are more or less on the correct path - but - you have made innumerable mistakes/typos - please fix those following my hints.

4x-3y=2
2x+y=-4-3 --- Where did -3 come from? Are you multiplying the equation by 3? Then you should say "multiplying by 3"

(6x+3y=-12)
-(4x-3y=2)= --- Why do you have "-" in front? Are you subtracting? But looking at the next line I see that you are actually adding (as you should)
10x=-10
x=-10/10=-1
x=1 --- Incorrect - where did the "-" sign go?

4(-1)=3y=2 <<< Typo - the first "=" sign should be "-"
-4-3y=2
-3=6 <<< Where did "y" go"
y=2--- Incorrect - where did the "-" sign go?

is the answer c. or d. i'm guessing with d.--- Incorrect