No idea where to start with this problem on functions Calc I

[Calculista222]

Stuck hard on this one :|

 

[tkhunny]

Re: No idea where to start with this problem on functions Ca

Perhaps this will help...

$\displaystyle \frac{f(x)}{g(x)} = f(x) \cdot \frac{1}{g(x)} = f(x) \cdot (g(x))^{-1}$

 

[Queenisabella87]

Re: No idea where to start with this problem on functions Ca

Can you elaborate in words please? :| tried going backwards from your response and im stumped!

 

[tkhunny]

Re: No idea where to start with this problem on functions Ca

Use the product rule on f(x) * h(x)

$\displaystyle \frac{d}{dx}(f(x)\cdot h(x)) = f(x)\cdot h'(x) + h(x)\cdot f'(x)$

Repeat the exercise after substituting $\displaystyle h(x) = (g(x))^{-1}$ -- Time for the Chain Rule on this one.