No idea where to start with this problem on functions Calc I

Re: No idea where to start with this problem on functions Ca

Perhaps this will help...

\(\displaystyle \frac{f(x)}{g(x)} = f(x) \cdot \frac{1}{g(x)} = f(x) \cdot (g(x))^{-1}\)
 
Re: No idea where to start with this problem on functions Ca

Can you elaborate in words please? :| tried going backwards from your response and im stumped!
 
Re: No idea where to start with this problem on functions Ca

Use the product rule on f(x) * h(x)

\(\displaystyle \frac{d}{dx}(f(x)\cdot h(x)) = f(x)\cdot h'(x) + h(x)\cdot f'(x)\)

Repeat the exercise after substituting \(\displaystyle h(x) = (g(x))^{-1}\) -- Time for the Chain Rule on this one.
 
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