no clue

[Sophiesmark]

I have no clue how to do this one, its an assigned problem but I dont think we ever went over this in class
h(x)= 3sin(4(x-2))+5

thanks for any help you can give, Im so glad i stumbled across this site!

 

[tkhunny]

Is there a problem statement?

 

[Sophiesmark]

Sorry,
find the first and second derivatives

 

[tridelta246]

I have no clue how to do this one, its an assigned problem but I dont think we ever went over this in class
h(x)= 3sin(4(x-2))+5

thanks for any help you can give, Im so glad i stumbled across this site!

If this problem was similar to your previous post, you'll want to compute h'(x)
using the Chain Rule:
h(x) = f(g(x)) where
f(x) = 3sin(x) + 5
g(x) = {4(x - 2)}
so that by the Chain Rule:
h'(x) = f'(g(x))*g'(x) = {3cos(4(x-2))}*{4} = 12*cos(4(x-2))

Repeat use of Chain Rule to find h''(x).

.

 

[Sophiesmark]

whoohoo got it, thanks!