Hi.., I have the answer from the book but I'm too stupid to figure out. Help me, please.
N notgnsatall New member Joined Aug 2, 2020 Messages 2 Aug 2, 2020 #1 Hi.., I have the answer from the book but I'm too stupid to figure out. Help me, please.
D Deleted member 4993 Guest Aug 2, 2020 #2 notgnsatall said: Hi.., I have the answer from the book but I'm too stupid to figure out. Help me, please. View attachment 20779 Click to expand... Do you the method of finding roots using Newton's method? If not - please do a google search with the keywords "Newton's method of finding roots o polynomials". Please show us what you have tried and exactly where you are stuck. Please follow the rules of posting in this forum, as enunciated at: https://www.freemathhelp.com/forum/threads/read-before-posting.109846/#post-486520 Please share your work/thoughts about this problem. You can solve the problem with simple algebra - but you have been retricted to Newton's method in this case.
notgnsatall said: Hi.., I have the answer from the book but I'm too stupid to figure out. Help me, please. View attachment 20779 Click to expand... Do you the method of finding roots using Newton's method? If not - please do a google search with the keywords "Newton's method of finding roots o polynomials". Please show us what you have tried and exactly where you are stuck. Please follow the rules of posting in this forum, as enunciated at: https://www.freemathhelp.com/forum/threads/read-before-posting.109846/#post-486520 Please share your work/thoughts about this problem. You can solve the problem with simple algebra - but you have been retricted to Newton's method in this case.
Steven G Elite Member Joined Dec 30, 2014 Messages 14,598 Aug 2, 2020 #3 [math] 404 = 400 + \dfrac{8d^2}{3*400} - \dfrac{32d^4}{5*400^3}[/math]. Now solve this using Newton's Method BTW I am assuming that [math]l= L[/math]. You really should have stated that or not use both [math]l\ and\ L[/math]
[math] 404 = 400 + \dfrac{8d^2}{3*400} - \dfrac{32d^4}{5*400^3}[/math]. Now solve this using Newton's Method BTW I am assuming that [math]l= L[/math]. You really should have stated that or not use both [math]l\ and\ L[/math]