A thermometer is removed from a room to the outside where the temp is 5 degrees F. After 1 min, the thermometer reads 55 F, and after 5 mins it reads 30 F. What is the initial temp of the room?
Ok, so here's what I know..
dT/dt = k(T - M), and M = 5 F.
T(1) = 55, T(5) = 30
Here's what I want to know...
T(0) = ?
I decided to start off this problem by plugging in numbers and solving for T:
dT/dt = k(T - 5)
dT/|T - 5 | = k dt //by separation of variables
ln |T - 5| = kt + C //after integration
T - 5 = Ce^kt //after exponentiation
Here's where I get stuck. I'm not sure how to find C or k using the information I've been given. The closest I can come up with is..
T(0) = 5 + C
T - 5 = C
T = 5 + (T - 5)e^(kt - 1)
But this doesn't seem right to me.
Thanks in advance,
Hank
Ok, so here's what I know..
dT/dt = k(T - M), and M = 5 F.
T(1) = 55, T(5) = 30
Here's what I want to know...
T(0) = ?
I decided to start off this problem by plugging in numbers and solving for T:
dT/dt = k(T - 5)
dT/|T - 5 | = k dt //by separation of variables
ln |T - 5| = kt + C //after integration
T - 5 = Ce^kt //after exponentiation
Here's where I get stuck. I'm not sure how to find C or k using the information I've been given. The closest I can come up with is..
T(0) = 5 + C
T - 5 = C
T = 5 + (T - 5)e^(kt - 1)
But this doesn't seem right to me.
Thanks in advance,
Hank