A sledge of mass 16kg is being pulled up the side of a hill of inclination 25degrees, at a constant velocity. The coefficient of friction between the sledge and the hill is 0.4, and the rope pulling the sledge exerts a force of magnitude T newtons at 15degrees to the horizontal.
What is the magnitude of tension in the rope and what is the magnitude of the normal reaction between the hill and the sledge?
I tried doing this-
Perpendicular: 16gcos25 = tsin15
parallel: 16gsin25= tcos15
16gsin25/cos15= t
156tan(25/15)= t. (wasn't sure where to post mechanics questions)
What is the magnitude of tension in the rope and what is the magnitude of the normal reaction between the hill and the sledge?
I tried doing this-
Perpendicular: 16gcos25 = tsin15
parallel: 16gsin25= tcos15
16gsin25/cos15= t
156tan(25/15)= t. (wasn't sure where to post mechanics questions)