New problem to solve

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Belby

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Sep 2, 2009
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This is the only one I have missed today. I am not sure if the answer is correct or if it is the way I am trying to enter into the homework site that it is not accepting the problem. Someone please check the answer for me and see if I have it correct.

Solve the equation of 6x^2 y +4y=2x for y as a function of x. Express your answer in calculator syntax form.

This is how I worked it.
6x^2y +4y=2x
y(6x^2+4)/6x^2+4=2x/6x^2+4
y=2x/6x^2+4
 


If you don't at first recognize that each term contains a factor of 2 (i.e., if you don't start as Denis did), then you'll need to factor out a 2 from the denominator of your result later.

\(\displaystyle y \;=\; \frac{2x}{6x^2 + 4}\)

\(\displaystyle y \;=\; \frac{2x}{2(3x^2 + 2)}\)

Cancel the common factor of 2 in the numerator and denominator, now. 8-)

 
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