A rectangular container with a square base and a volume of 128 ft^3. The cost of the materials for the top and four sides is $2 per ft ^2. The cost of the materials for the bottom is $6 per ft^2. Find the dimensions of the box that minimizes the cost of the materials, and find the minimum cost.
So far, I have x^2(h)=128
h=128/x^2
Cost = 6x^2+10(128/x^2)
Is this the way to begin? Don't I need to take the derivative of something in order to minimize.
Thanks
So far, I have x^2(h)=128
h=128/x^2
Cost = 6x^2+10(128/x^2)
Is this the way to begin? Don't I need to take the derivative of something in order to minimize.
Thanks