Need to Solve for C

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filya

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Jul 1, 2019
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Hi,
I'm new here and have a formula that I've been trying so solve. I tried online solvers but I'm having issues figuring it out

E=((A*(1/B-1/C)))/D*100

Need to solve for C

Any help appreciated!

Thank you in advance!
 
filya said:
Hi,
I'm new here and have a formula that I've been trying so solve. I tried online solvers but I'm having issues figuring it out

E=((A*(1/B-1/C)))/D*100

Need to solve for C

Any help appreciated!

Thank you in advance!
Click to expand...
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Hint: To solve for 'C' you need to isolate 'C'. If I were to do this problem my first would be rewrite the equation as:

E * D/100 = A * (1/B - 1/C)

Now continue......
 
I'll be honest, I'm really bad at math.

To put more perspective behind the formula... It is used to to calculate Unrealized Profit and Loss Percentage in Bitmex. I would like to figure out the Price on the hypothetical Unrealized Profit and Loss Percentage

E=((A*(1/B-1/C)))/D*100
Unrealized Profit and Loss percentage = ((Contracts*(1/Entry Price - 1/Current Price)/Account Balance*100 in BTC*100

I've tried online solvers and it provided me the following answer but when I plug it in the numbers don't add up.
C=-((100AB)/(EBD-100A))
 
Last edited:
Looks straight forward to me. To "solve for C", undo everything that has been done to C, in the opposite order.
Here, calculate E=((A*(1/B-1/C)))/D*100, the last thing you would do is divide by D*100. So to "undo" that multiply by D*100. On both sides, of course. That gives 100*D*E= A*(1/B- 1/C). A is multiplying everything on the right side so get rid of it by dividing both sides by A: 100*D*E/A= 1/B- 1/C.

There is a "1/B" on the right side so subtract 1/B from both sides: 100*D*E/A- 1/B= -1/C.
Multiply both sides by -1: 1/B- 100*D*E/A= 1/C.
Now take the reciprocal of both sides:
C= 1/(1/B- 100*D*E/A)

That is the answer but you might want to simplify the right side:
Get the common denominator AB: 1/B- 100*D*E/A= A/AB- 100*D*E*B/AB= (A- 100*D*E*B)/AB
so C= AB/(A- 100*D*E*B).
 
Last edited:
HallsofIvy said:
Looks straight forward to me. To "solve for C", undo everything that has been done to C, in the opposite order.
Here, calculate E=((A*(1/B-1/C)))/D*100, the last thing you would do is divide by D*100. So to "undo" that multiply by D*100. On both sides, of course. That gives 100*D*E= A*(1/B- 1/C). A is multiplying everything on the right side so get rid of it by dividing both sides by A: 100*D*E/A= 1/B- 1/C.

There is a "1/B" on the right side so subtract 1/B from both sides: 100*D*E/A- 1/B= -1/C.
Multiply both sides by -1: 1/B- 100*D*E/A= 1/C.
Now take the reciprocal of both sides:
C= 1/(1/B- 100*D*E/A)

That is the answer but you might want to simplify the right side:
Get the common denominator BA: 1/B- 100*D*E/A= A/AB- 100*D*E*B/AB= (A- 100*D*E*B)/AB
so C= AB/(A- 100*D*E*B).
Click to expand...
HoI - seems that you are reading the given expression with having a denominator with (D*100). If it is - then the OP posted an incorrect problem (without the grouping symbol of parentheses)
 
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