Need To Solve EV = log2 ( (100 * aperture² ) / ( ISO * time ) ) For "time"

[skleczka]

Need To Solve EV = log2 ( (100 * aperture² ) / ( ISO * time ) ) For "time"

Good Afternoon! Could anyone help me rearrange this formula in order to solve for "time"?

EV = log2 ( (100 * aperture² ) / ( ISO * time ) )

Thank you very much!!!

 

[Deleted member 4993]

Good Afternoon! Could anyone help me rearrange this formula in order to solve for "time"?

EV = log2 ( (100 * aperture² ) / ( ISO * time ) )

Thank you very much!!!

Multiply by "time" (t) - both sides of equation, then,

Divide by "EV" - both sides of equation.

What do you get?

 

[Ishuda]

Multiply by "time" (t) - both sides of equation, then,

Divide by "EV" [2^EV?] - both sides of equation.

What do you get?

After raising everything to the power of two?

 

[Deleted member 4993]

Multiply by "time" (t) - both sides of equation, then,

Divide by "EV" - both sides of equation.

What do you get?

OOoops .... correction

EV = log₂ [(100 * aperture²) / (ISO * time)] ................ would have been easier to detect if you had used different parentheses.

2^EV = (100 * aperture²) / (ISO * time)

Now

Multiply by "time" (t) - both sides of equation, then,

Divide by "2^EV" - both sides of equation.

from the corner....

 

[stapel]

Could anyone help me rearrange this formula in order to solve for "time"?

EV = log2 ( (100 * aperture² ) / ( ISO * time ) )

Does "log2" indicate "multiplied by log₁₀(2)", "multiplied by log_e(2)", "log, base two, of the parenthetical", or something else? Thank you!