need some help

[xc630]

hi this equation is giveing me trouble.

SQRT (4^x+3)/ (16^ x) = 32

I squared both sides but form there Im stuck.

 

[stapel]

You appear to have:

. . . . .sqrt[4^x + 3] / 16^x = 32

Squaring both sides would yield:

. . . . .(4^x + 3) / 16^2x = 1024 = 16^2.5

Multiply up to get:

. . . . .4^x + 3 = 16^{2x + 2.5}

I'm not sure where you're supposed to go from there, though.

Eliz.

 

[tkhunny]

What was the result after you squared it?

 

[xc630]

I think I got it
(4^x+3)/(16^x)= 1024

4^x+3 = 16384^x

4^x+3= 4^7

x+3= 7
x=4

 

[Denis]

I think I got it
(4^x+3)/(16^x)= 1024

4^x+3 = 16384^x : HUH? that should be 4^x + 3 = 1024(16^x)

Suggestion: go check your original equation: doesn't make much sense;
did you realise that with x=4, then 16384^4 = 72,057,594,037,927,936 ?

 

[xc630]

Ok i got x=-2

 

[Gene]

I'm still not sure what the problem is. Some of your work says the exponent of the first 4 is x+3 and that the 16^x is under the radical. If that is true it sould be typed
sqrt[4^(x+3)/16^x]=32
When you square both sides
[4^(x+3)/4^(2x)]=4^5
4^(x+3)=4^(2x+5)
x+3=2x+5
x=-2 as you said. But it has nothing to do with what you typed.
There should be ( ) or [ ] or { } around every "sqrt". Around every thing under the radical. I used [ ].
Any exponent can have () around it and if it is more than one character it must have. If I had typed 4^2x it would have meant 4*4*x.
Any group of terms in the denominator needs them too.
It is better to have more than you need than too few.