Need much help!

[sarahjoy00]

1.) x^3-6x+x^2-6=0

2.) x^2+5x+6 is greater than or equal to 0

3.) f(x)=-x^2+2x+3

4.) f(x)=x^2+5x+4

5.) f(x)=-6x^2-12x-5

6.) x^2+6x

 

[Mrspi]

1.) x^3-6x+x^2-6=0

2.) x^2+5x+6 is greater than or equal to 0

3.) f(x)=-x^2+2x+3

4.) f(x)=x^2+5x+4

5.) f(x)=-6x^2-12x-5

6.) x^2+6x

You've posted a bunch of problems, with NO directions about what you are asked to do.

You haven't posted any of your work, either.

We don't DO homework here (especially if we don't know what you're asked to do!!)

Take each problem you've listed, tell us what the specific directions are for the problem, and show us all of the work you've done to try to solve the problem. THEN we can address how best to help you.

 

[fasteddie65]

1.) x^3 - 6x + x^2 - 6 = 0
x^2(x - 6) + 1(x - 6) = 0
(x - 6)(x^2 + 1) = 0
x - 6 = 0 or x^2 + 1 = 0
x = 6 x^2 = -1
x = ±i

2.) x^2 + 5x + 6 is greater than or equal to 0
(x + 2)(x + 3) ? 0
x ? -3 or x ? -2

3.) f(x) = -x^2 + 2x + 3
This function has a parabolic graph, with vertex (1, 4), opening downward, with x-intercepts -1 and 3.

4.) f(x) = x^2 + 5x + 4
This function has a parabolic graph, with vertex (-5/2, -9/4), opening upward, with x-intercepts -1 and -4.

5.) f(x) = -6x^2 - 12x - 5
This function has a parabolic graph, with vertex (-1, 1), opening downward. Its x-intercepts have irrational coordinates.

6.) x^2 + 6x = x(x + 6)
If this were an equation, its solutions would be 0 and -6.