Need Help.

[djm1951]

Good Day to all. I am stuck in a problem and not sure what/how to finish it.
Original Problem: Find an equation of the line having the given slope & containing the given point. m=8/9, (6,-2).

This is what I have done so far using y-y1=m(x-x1)

y-(-2)=(8/9)(x-6)
y+2=8/9x+6

So I believe I am suppose to subtact 1 from each side. Can you show me the steps on how to do this please. Thanks

 

[lookagain]

Good Day to all. I am stuck in a problem and not sure what/how to finish it.
Original Problem: Find an equation of the line having the given slope & containing the given point. m=8/9, (6,-2).

This is what I have done so far using y-y1=m(x-x1)


y - (-2) = (8/9)(x - 6)\(\displaystyle .\ . \ . \ . \ . \ . \ . \ . Please \ \ space \ \ out \ \ your \ \ typing \ \ for \ \ better \ \ readability,\)

\(\displaystyle \ \ as \ \ is \ \ suggested\ \ here.\)


\(\displaystyle y + 2 =(8/9)x + (8/9)6\)


\(\displaystyle The \ slope \ is \ multiplied \ by \ every \ term \ of \ the \ binomial.\)


So I believe I am suppose to subtact 1 from each side. Can you show me the steps on how to do this please. Thanks

\(\displaystyle y \ + \ 2 \ = \ \frac{8}{9}x \ + \ \frac{8}{9}\bigg(\frac{6}{1}\bigg)\)


Please finish it from here, if you would like to

 

[TchrWill]

I am stuck in a problem and not sure what/how to finish it.
Original Problem: Find an equation of the line having the given slope & containing the given point. m=8/9, (6,-2).

This is what I have done so far using y-y1=m(x-x1)

y-(-2)=(8/9)(x-6)
y+2=8/9x+6

So I believe I am suppose to subtact 1 from each side. Can you show me the steps on how to do this please. Thanks

You are given the slope and a point that the line passes through.

From y = mx + b, -2 = (8/9)(6) + b

b = -2 - (8/9)(6) + b = -2 - (48/9) = -18 - 48/9 = -66/9

Therefore, y = (8/9)x - 7.333