Need help

[rbr2hope4]

Problem #1 One of the complementary angles is less than twice the other angle. Find the measure of each angle.
Problem #2 One of the angles has a measure of 40 degrees. Find the measures of the other two angles if the difference of their measures is 10 degrees

 

[Mrspi]

Problem #1 One of the complementary angles is less than twice the other angle. Find the measure of each angle.
Problem #2 One of the angles has a measure of 40 degrees. Find the measures of the other two angles if the difference of their measures is 10 degrees

#1....do you know what complementary angles are?

And, have you LOOKED at the way you typed the problem? This makes NO sense: One of the complementary angles is less than twice the other angle. Find the measure of each angle.

Once you've gotten THAT figured out, write an expression for the measure of each of the angles, and use the definition of complementary angles.

For problem #2...I'm sorry...you cannot expect us to help with a problem for which we have not been provided with a diagram OR a complete explanation.

 

[LivingMath]

These are algebra problems that rely on some knowledge of geometry.

1. Complementary angles sum to 90 degrees. If angle A is x degrees, then angle B is >= 2x degrees.

2. Since there are only 3 angles in the description, I assume this is a triangle problem. The angles of a triangle sum to 180 degrees. Let x be one of the unknown angles. Then x + 10 is the other unknown angle. Then 40 + x + (x + 10) = 180.

If there is more information for each problem, please post that to get a more complete answer.