Need Help

bamby

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Aug 5, 2009
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5
A spherical baloon is inflated with a gas at rate 500cm3/min. How fast is the radius of the baloon increasing at the instant the n is 30 cm?

Thanks?
 
VSphere = 43πr3\displaystyle V_{Sphere} \ = \ \frac{4}{3} \pi r^{3}

dVdt = 4πr2drdt\displaystyle \frac{dV}{dt} \ = \ 4\pi r^{2}\frac{dr}{dt}

Now dVdt = 500 and when r = 30, then 500 = 4π(302)drdt\displaystyle Now \ \frac{dV}{dt} \ = \ 500 \ and \ when \ r \ = \ 30, \ then \ 500 \ = \ 4\pi(30^{2})\frac{dr}{dt}

Therefore, drdt = 536π cm/min\displaystyle Therefore, \ \frac{dr}{dt} \ = \ \frac{5}{36\pi} \ cm/min

Note: I'm assuming that n = radius, not diameter.
 
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