magdaddy101
New member
- Joined
- Oct 4, 2009
- Messages
- 6
I'm supposed to find the solution this initial value problem using the method of undetermined coefficients
y'' - 2y' - 3y = 3te^(2t), y(0)=1, y'(0)=0.
My guess was to use Y(t) = Ate^(2t) + Be^(2t) for the particular solution, but this led me to the wrong answer.
I have a hunch that I should use Y(t) = t(Ate^(2t) + Be^(2t)) but I have no idea why, since e^(2t) is not part of the complimentary solution.
I appreciate any help.
y'' - 2y' - 3y = 3te^(2t), y(0)=1, y'(0)=0.
My guess was to use Y(t) = Ate^(2t) + Be^(2t) for the particular solution, but this led me to the wrong answer.
I have a hunch that I should use Y(t) = t(Ate^(2t) + Be^(2t)) but I have no idea why, since e^(2t) is not part of the complimentary solution.
I appreciate any help.