Need help with this triangle inside of a semicircle problem. Pre-Calc.

[jackz2003]

Specifically need help on part B, at a complete loss for what I need to do.

 

[Deleted member 4993]

Specifically need help on part B, at a complete loss for what I need to do.

Hint: use the fact that the measure of the angle BCA is 90^o.Then use the well-known formula for area of a triangle using 'x' as the base.

Please show us what you have tried and exactly where you are stuck.​

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Please share your work/thoughts about this assignment.​

 

[pka]

Specifically need help on part B, at a complete loss for what I need to do.

Re-ornate your thinking so that \(\overline{AC}\) is the base of \(\Delta ACB\) and has length \(x\).
The right triangle \(\Delta ACB\) has height \(y\). Moreover, we know that the height is \(y=\sqrt{225-x^2}\).
Recalling that the area of any triangle is one-half the length of its base times the height.
Using this help please post the answer to the part (b).