Need Help with this problem!

[ieatrum]

the question is [math]f(x)=\frac{x^2+7}{x^2+4}[/math], and im trying to find the vertical and horizontal asymptotes. I found the horizontal, but not the vertical. The way I know to solve for the vertical asymptote is to equal the denominator to 0; which is what I did. That gives me x=-2,-2, which I inputted to my assignment, but it came back as incorrect. I know the answer is DNE for the vertical asymptote, but I want to know how to get it without looking at a graph.

 

[mmm4444bot]

for the vertical asymptote is to equal the denominator to 0; which is what I did. That gives me x=-2,-2

Hello. The denominator (x^2+4) is never zero, for any Real x. You're adding a non-negative number (x^2) to a positive number (4). The denominator must be greater than or equal to 4.

You'd solved x^2 – 4 = 0, instead.

?
[imath]\;[/imath]

 

[Steven G]

(2)^2 + 4 = 0?
(-2)^2 + 4 =0?
For the record, 4+4=8