Need help with Precal: Limit of an infinite Geometric Sequence

[Psilocyde]

They give me the first three terms: √3, 1, √3/3

The answer the textbook gives me is 3/2( √3+1), but I can't for the life of me think of how to get there.

 

[Deleted member 4993]

They give me the first three terms: √3, 1, √3/3

The answer the textbook gives me is 3/2( √3+1), but I can't for the life of me think of how to get there.

If the series is a, ar, ar² - how do you calculate the value of 'r'?

What is the 'r' in this case? What is the 'a' in this case?

By the way, you have not specified - what limit that you want to calculate. From the answer, I gather that you want to calculate the limit of the sum the series.

 

[pka]

They give me the first three terms: √3, 1, √3/3
The answer the textbook gives me is 3/2( √3+1), but I can't for the life of me think of how to get there.

Here is the arithmetic:
\(\displaystyle \dfrac{\sqrt{3}}{1-\frac{1}{\sqrt{3}}}=\\\dfrac{3}{\sqrt{3}-1}=\\\dfrac{3(\sqrt{3}+1)}{2}.\)