NEED help with LOG!

darkcr0ss

New member
Joined
Aug 8, 2010
Messages
2
I need help to find this solution Im so clueless about logs..

PLease help

2-Log10^100
 
There is a logarithmic property that tells us how to simplify this.

log(10^100) = 100 * log(10)

In other words, if a logarithm's input is written as a power (like 10^100), we can move the exponent "out in front".

Stated symbolically, the property looks like this:

log(b^x) = x * log(b)


You can use this property to rewrite the given expression:

2 - log(10^100)

2 - 100 * log(10)

2 - 100

-98

Why are you clueless about logarithms ?

Do you know what an exponent is? Logarithms are just another way of writing an exponent.
 
Me and precalc dont mix...
Lets just say that..

But thanks alot you really cleared it up for me.
 
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