waffles383
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- Dec 8, 2008
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okay. this is the same type of problem i guess, but it confuses me so much! :?
(2/3)a + 2 = 1/3(4a + 1)
(2/3)a + 2 = 1/3(4a + 1)
need help with (2 / 3) a + 2 = 1 / 3 (4a + 1)
- Thread starter waffles383
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Re: need help again!
It's very hard to tell from the way you've written the expression exactly what quantity is over what and so on. I really can't figure out what the problem is.
But to try something plausible...
(2/3)a + 2 = 1/3(4a + 1)
probably means
\(\displaystyle \frac{2}{3} a + 2 = \frac{1}{3} (4a + 1)\)
I'll take one step, and then you go from there (or correct me if I'm reading the problem wrong). We have to solve for a, which is what I assume the instructions said for this worksheet. We can rewrite the above equation as follows:
\(\displaystyle \frac{2 a + 6}{3} = \frac{4 a + 1}{3}\)
Take it away ...
It's very hard to tell from the way you've written the expression exactly what quantity is over what and so on. I really can't figure out what the problem is.
But to try something plausible...
(2/3)a + 2 = 1/3(4a + 1)
probably means
\(\displaystyle \frac{2}{3} a + 2 = \frac{1}{3} (4a + 1)\)
I'll take one step, and then you go from there (or correct me if I'm reading the problem wrong). We have to solve for a, which is what I assume the instructions said for this worksheet. We can rewrite the above equation as follows:
\(\displaystyle \frac{2 a + 6}{3} = \frac{4 a + 1}{3}\)
Take it away ...
waffles383
New member
- Joined
- Dec 8, 2008
- Messages
- 5
Re: need help again!
thank you! it makes so much more sense now!
thank you! it makes so much more sense now!