need help w/ finding point of intersection of line w/ plane

[Laurenmath]

I need to find the point of intersection of the line given by parametric equations x = 3 + 2t, y = 7 + 8t, and z = -2 + t with the y,z-plane.

 

[galactus]

Hello Lauren:

Where are you hung up?.

 

[Laurenmath]

repy

i dont know where to start

 

[pka]

All the points in the yz-plane look like: (0,y,z).

 

[Laurenmath]

i still am confused.. i know a point is (3,7,-2) and a vector is < 2,8,1> then what does that do for me??

 

[skeeter]

i still am confused.. i know a point is (3,7,-2) and a vector is < 2,8,1> then what does that do for me??

x = 3 + 2t, y = 7 + 8t, and z = -2 + t

using pka's hint ... (x = 0, right?)

x = 3 + 2t = 0
t = -3/2

y = 7 + 8(-3/2)

z = -2 + (-3/2)

so ... where's the point of intersection on the y-z plane?

 

[Laurenmath]

so the point of intersection would be (0,-5,-3.5) right?