need help please!!!

nova720

New member
Joined
Jan 17, 2011
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3
11.55 = y + ((111.1^2)/(2*32.2*y^2))

i cant figure out how to solve this problem. need to know the steps involved.
 
nova720 said:
11.55 = y + ((111.1^2)/(2*32.2*y^2))

i cant figure out how to solve this problem. need to know the steps involved.

Hi nova720,

Looks like this is what you have:

\(\displaystyle 11.55=y+\frac{111.1^2}{2 \cdot32.2 \cdot y^2}\)

Clean it up a bit.

\(\displaystyle 11.55=y+\frac{12343.21}{64.4y^2}\)

\(\displaystyle 11.55=y+\frac{191.6614907}{y^2}\)

\(\displaystyle 11.55y^2=y^3+191.6614907\)

\(\displaystyle y^3-11.55y^2+191.6614907=0\)

All roots are real. Use a graphing calculator to estimate these roots.
 
nova720 said:
11.55 = y + ((111.1^2)/(2*32.2*y^2))

i cant figure out how to solve this problem. need to know the steps involved.

Are you sure your problem does NOT look like:

\(\displaystyle 11.55 \ = \ y \ + \ \frac{111.1^2}{2*32.2}*y^2\)
 
No, the original equation was correct. I reduced it to what was shown, but I still don't know how to find the solutions.
 
nova720 said:
No, the original equation was correct. I reduced it to what was shown, but I still don't know how to find the solutions.

Roots of these equations can be estimated through Newton-Raphson method. Have you taken any numerical analysis course where that method has been taught?

Other than that - use your graphing calculator to estimate the roots.
 
Thanks I really appreciate your help. I used the graphing calculator to determine the solutions. Thanks!!!!
 
nova720 said:
I used the graphing calculator to determine the solutions.
Nova, what solutions do you get for: y^3 - 9y^2 + 98 = 0 ?
 
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